S. K. Gupta Anubhuti Gangal Class 5 Math Fifteenth Chapter Perimeter And Area Exercise 53
EXERCISE 53
(1) Find the length of the rectangle whose:
(a) Area = 320 sq. cm and breadth = 16 cm
Solution: Length = (320 ÷ 16) cm = 20 cm
(b) Area = 1800 sq. cm and breadth = 40 cm
Solution: Length = (1800 ÷ 40) cm = 450 cm
(c) Area = 216 sq. cm breadth = 12 cm
Solution: Length = (216 ÷ 12) cm = 18 cm
(2) Find the breadth of the rectangle whose:
(a) Area = 187 cm2 and length = 17 cm
Solution: Breadth = (187 ÷ 17) cm = 11 cm
(b) Area = 315 mm2 and length = 21 mm
Solution: breadth = (315 ÷ 21) mm = 15 mm
(c) Area = 10000 m2 and length = 100 m
Solution: Length = (10000 ÷ 100) m = 100 m
(3) Find the perimeter of a rectangle whose:
(a) Area = 1050 sq. cm, length = 35 cm
Solution: Breadth = (1050 ÷ 35) cm = 30 cm
∴ Perimeter = [2 × (35+30)] cm = (2 × 65) cm = 130 cm
(b) Area = 18 cm2, breadth = 6 cm
Solution: Length = (18 ÷ 6) cm = 3 cm
∴Perimeter = [2 × (3+6)] cm = (2 × 9) cm = 18 cm
(c) Area = 4800 m2, breadth = 60 m
Solution: Length = (4800 ÷ 60) m = 80 m
∴ Perimeter = [2 × (80+60)] m = (2 × 140) m = 280 m
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