RS Aggarwal Class 7 Mathematics First Chapter Integers Exercise 1D Solution

RS Aggarwal Class 7 Mathematics First Chapter Integers Exercise 1D Solution

EXERCISE 1D

OBJECTIVE QUESTIONS

Mark (√) against the correct answer in each of the following:

(1) 6 – (- 8)

= 6 + 8 = 14

Ans: (c)

(2) – 9 – (- 6)

= – 9 + 6 = – 3

Ans: (b)

(3) By how much does 2 exceed – 3?

= 2 – ( – 3)

= 2 + 3 = 5

Ans: (d)

(4) What must be subtracted from – 1 to get – 6?

= – 1 – (- 6)

= – 1 + 6 = 5

Ans: (a)

(5) How much less than – 2 is – 6?

= – 2 – (- 6)

= – 2 + 6 = 4

Ans: (a)

(6) On subtracting 4 from – 4, we get

= – 4 – 4 = – 8

Ans: (b)

(7) By how much does – 3 exceed – 5?

= – 3 – (- 5)

= – 3 + 5 = 2

Ans: (b)

(8) What must be subtracted from – 3 to get – 9?

= – 3 – (- 9)

= – 3 + 9 = 6

Ans: (c)

(9) On subtracting 6 from – 5, we get

= – 5 – 6 = – 11

Ans: (c)

(10) On subtracting – 13 from – 8, we get

= – 8 – (- 13)

= – 8 + 13 = 5

Ans: (c)

(11) (- 36) ÷ (- 9)

Ans: (a)

(12) 0 ÷ (- 5)

= 0

Ans: (b)

(13) (- 8) ÷ 0

Ans: (c)

(14) Which of the following is a true statement?

Ans: (b) – 11 < – 8

(15) The sum of two integers is 6. If one of them is – 3, then the other is

= 6 – (- 3)

= 6 + 3  = 9

Ans: (b)

(16) The sum of two integers is – 4. If one of them is 6, then the other is

= – 4 – 6 = – 10

Ans: (a)

(17) The sum of two integers is 14. If one of them is – 8, then the other is

= 14 – (- 8)

= 14 + 8 = 22

Ans: (a)

(18) The additive inverse of – 6 is

Ans: (c)

(19) (- 15) × 8 + (- 15) × 2

= – 120 + (- 30)

= – 120 – 30 = – 150

Ans: (b)

(20) (- 12) × 6 – (- 12) × 4

= – 72 – (- 48)

= – 72 + 48 = – 24

Ans: (b)

(21) (- 27) × (- 16) + (- 27) × (- 14)

= 432 + 378 = 810

Ans: (b)

(22) 30 × (- 23) + 30 × 14

= – 690 + 420 = – 270

Ans: (a)

(23) The sum of two integers is 93. If one of them is – 59, the other one is

= 93 – (- 59)

= 93 + 59 = 152

Ans: (c)

(24) (?)÷ (- 18) = – 5

= (- 18) × (- 5)

= 90

Ans: (b)

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