RS Aggarwal Class 6 Math Seventh Chapter Decimals Exercise 7D Solution
EXERCISE 7D
Subtract:
(1) 27.86 from 53.74
Solution: Converting the given decimals into like decimals, we get 27.86 and 53.74
Writing them in column form with the larger one at the top and subtracting, we get:
53.74
-27.86
25.88
(2) 64.98 from 103.87
Solution: Converting the given decimals into like decimals, we get 64.98 and 103.87
Writing them in column form with the larger one at the top and subtracting, we get:
103.84
-64.98
38.89
(3) 59.63 from 92.4
Solution: Converting the given decimals into like decimals, we get 59.63 and 92.40
Writing them in column form with the larger one at the top and subtracting, we get:
92.40
-59.63
32.77
(4) 56.8 from 204
Solution: Converting the given decimals into like decimals, we get 56.8 and 204.0
Writing them in column form with the larger one at the top and subtracting, we get:
204.4
-56.8
147.2
(5) 127.38 from 216.2
Solution: Converting the given decimals into like decimals, we get 127.38 and 216.20
Writing them in column form with the larger one at the top and subtracting, we get:
216.20
-127.38
88.82
(6) 39.875 from 70.68
Solution: Converting the given decimals into like decimals, we get 39.875 and 70.680
Writing them in column form with the larger one at the top and subtracting, we get:
70.680
-39.875
30.805
(7) 348.237 from 523.12
Solution: Converting the given decimals into like decimals, we get 348.237 and 523.120
Writing them in column form with the larger one at the top and subtracting, we get:
523.120
-348.237
174.883
(8) 458.573 from 600
Solution: Converting the given decimals into like decimals, we get 458.573 and 600.000
Writing them in column form with the larger one at the top and subtracting, we get:
600.000
-458.573
141.427
(9) 149.456 from 206.321
Solution: Converting the given decimals into like decimals, we get 149.456 and 206.321
Writing them in column form with the larger one at the top and subtracting, we get:
206.321
-149.456
56.865
(10) 0.612 from 3.4
Solution: Converting the given decimals into like decimals, we get 0.612 and 3.400
Writing them in column form with the larger one at the top and subtracting, we get:
3.400
-0.612
2.788
Simplify:
(11) 37.6 + 72.85 – 58.678 – 6.09
= (37.600 + 72.850) – (58.678 +6.090) [converting like decimals]
= 110.45 – 64.768
= 45.682
(12) 75.3 – 104.645 + 178.96 – 47.9
= (75.300 + 178.960) – (104.645 + 47.900) [converting like decimals]
= 254.26 – 152.545
= 101.715
(13) 213.4 – 56.84 – 11.87 – 16.087
= 213.400 – (56.840 + 11.870 + 16.087) [converting like decimals]
= 213.400 – 84.797
= 128.603
(14) 76.3 – 7.666 – 6.77
= 76.300 – (7.666 + 6.770) [converting like decimals]
= 76.300 – 14.436
= 61.864
(15) What is to be added to 74.5 to get 91?
Solution: Converting the given decimals into like decimals, we get 74.5 and 91.0
So, (91.0 – 74.5) = 16.5
Ans: 16.5 is to be added to 74.5 to get 91.
(16) What is to be subtracted from 7.3 to get 0.862?
Solution: Converting the given decimals into like decimals, we get 7.300 and 0.862
So, (7.300 – 0.862) = 6.438
Ans: 6.438 is to be subtracted from 7.3 to get 0.862
(17) By how much should 23.754 decreased to get 50?
Solution: Converting the given decimals into like decimals, we get 23.754 and 50.000
So, (50.000 – 23.754) = 26.246
(18) By how much should 84.5 be decreased to get 27.84?
Solution: : Converting the given decimals into like decimals, we get 84.50 and 27.84
So, (84.50 – 27.884) = 56.66
(19) If the school bags of Neelam and Garima weigh 6 kg 80 g and 5 kg 265 g respectively, whose bag is heavier and by how much?
Solution: We have:
Weigh of Neelam’s bag 6.080 kg
Weigh of Garima’s bag 5.265 kg
So, (6.080 – 5.265) = 0.815 kg = 815 g
Hence,815 g Neelam’s bag is heavier from Garima’s bag.
(20) Kunal purchased a notebook for Rs 19.75, a pencil for Rs 3.85 and a pen for Rs 8.35 from a book shop. He gave a 50-rupee note to the shopkeeper. What amount did he get back?
Solution: Total money paid = 50.00 rupee
Cost of notebook = 19.75 rupee
Cost of pencil = 3.85 rupee
Cost of pen = 8.35 rupee
Thus, 50.00 – (19.75 + 3.85 + 8.35)
= 50.00 – 31.95
= 18.05
Hence, kunal get back 18.05 rupee.
(21) Sunita purchased 5 kg 75 g of fruits and 3 kg 465 g of vegetables, and put them in a bag. If this with these contents weighs 9 kg, find the weight of the empty bag.
Solution: The contents weigh of bag = 9.000 kg
The weight of fruits = 5.075 kg
The weight of vegetables = 3.465 kg
Thus, 9.000 – (5.075 + 3.465)
= 9.000 – 8.540
= 0.46 kg = 460 g
Hence, the weight of the empty bag is 460 g.
(22) The distance between Reeta’s house and her office is 14 km. She covers 10 km 65 m by scooter, 3 km 75 m by bus and the rest on foot. How much distance does she cover by walking?
Solution: Distance covered by scooter = 10.65 km
Distance covered by bus = 3.75 km
Total distance covered by scooter and bus = (10.65 + 3.75) = 13 km 140 m
Total distance to be covered by Reeta = 14.0 km
Distance covered by walking = 14.000 – 13.140 = 0.860 km = 860 m
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