NCERT Class 6 Mathematics Sixth Chapter Integers Exercise 6.3 Solution

NCERT Class 6 Mathematics Sixth Chapter Integers Exercise 6.3 Solution

EXERCISE 6.3

(1) Find

(a) 35 – (20)

= 35 – 20

= 15

(b) 72 – (90)

= 72 – 90

= – 8

(c) (– 15) – (– 18)

= – 15 + 18

= 3

(d) (–20) – (13)

= – 20 – 13

= – 33

(e) 23 – (– 12)

= 23 + 12

= 35

(f) (–32) – (– 40)

= – 32 + 40

= 8

(2) Fill in the blanks with >, < or = sign.

(a) (– 3) + (– 6) < (– 3) – (– 6)

= – 3 – 6 < – 3 + 6

= – 9 < + 3

(b) (– 21) – (– 10) > (– 31) + (– 11)

= – 21 + 10 > – 31 – 11

= – 11 > – 42

(c) 45 – (– 11) > 57 + (– 4)

= 45 + 11 > 57 – 4

= 56 > 53

(d) (– 25) – (– 42) > (– 42) – (– 25)

= – 25 + 42 > – 42 + 25

= 17 > – 17

(3) Fill in the blanks.

(a) (– 8) + 8 = 0

(b) 13 + (- 13) = 0

(c) 12 + (– 12) = 0

(d) (– 4) + (- 8) = – 12

(e) 5 – 15 = – 10

(4) Find

(a) (– 7) – 8 – (– 25)

= – 7 – 8 + 25

= – 15 + 25

= 10

(b) (– 13) + 32 – 8 – 1

= – 13 + 32 – 9

= 32 – 22

= 10

(c) (– 7) + (– 8) + (– 90)

= – 7 – 8 – 90

= – 15 – 90

= – 105

(d) 50 – (– 40) – (– 2)

= 50 + 40 + 2

= 90 + 2

= 92