RS Aggarwal Class 7 Mathematics Third Chapter Decimals Exercise 3C Solution
EXERCISE 3C
(1) Find the product:
(i) 73.92 × 10 = 739.2
(ii) 7.54 × 10 = 75.4
(iii) 84.003 × 10 = 840.03
(iv) 0.83 × 10 = 8.3
(v) 0.7 × 10 = 7
(vi) 0.032 × 10 = 0.32
(2) Find the product:
(i) 2.397 × 100 = 239.7
(ii) 6.83 × 100 = 683
(iii) 2.9 × 100 = 290
(iv) 0.08 × 100 = 8
(v) 0.6 × 100 = 60
(vi) 0.003 × 100 = 0.3
(3) Find the product:
(i) 6.7314 × 1000 = 6731.4
(ii) 0.182 × 1000 = 182
(iii) 0.076 × 1000 = 76
(iv) 6.25 × 1000 = 6250
(v) 4.8 × 1000 = 4800
(vi) 0.06 × 1000 = 60
(4) Find the product:
(i) 5.4 × 16
(ii) 3.65 × 19
(iii) 0.854 × 12
(iv) 36.73 × 48
(v) 4.125 × 86
(vi) 104.06 × 75
(vii) 6.032 × 124
(viii) 0.0146 × 69
(ix) 0.00125 × 327

(5) Find the product:
(i) 7.6 × 2.4
(ii) 3.45 × 6.3
(iii) 0.54 × 0.27
(iv) 0.568 × 4.9
(v) 6.54 × 0.09
(vi) 3.87 × 1.25

(vii) 0.06 × 0.38 = 0.0228
(viii) 0.623 × 0.75 = 0.46725
(ix) 0.014 × 0.46 = 0.00644
(x) 54.5 × 1.76 = 95.920
(xi) 0.045 × 2.4 = 0.1080
(xii) 1.245 × 6.4 = 7.9680
(6) Find the product:
(i) 13 × 1.3 × 0.13
= 16.9 × 0.13
= 2.197
(ii) 2.4 × 1.5 × 2.5
= 3.6 × 2.5
= 9
(iii) 0.8 × 3.5 × 0.05
= 2.8 × 0.05
= 0.14
(iv) 0.2 × 0.02 × 0.0002
= 0.004 × 0.0002
= 0.0000008
(v) 11.1 × 1.1 × 0.11
= 12.21 × 0.11
= 1.3431
(vi) 2.1 × 0.21 × 0.021
= 0.441 × 0.021
= 0.006261
(7) Evaluate:
(i) (1.2)2
= 1.2 × 1.2
= 1.44
(ii) (0.7)2
= 0.7 × 0.7
= 0.49
(iii) (0.04)2
= 0.04 × 0.04
= 0.0016
(iv) (0.11)2
= 0.11 × 0.11
= 0.0121
(8) Evaluate:
(i) (0.3)3
= 0.3 × 0.3 × 0.3
= 0.027
(ii) (0.05)3
= 0.05 × 0.05 × 0.05
= 0.000125
(iii) (1.5)3
= 1.5 × 1.5 × 1.5
= 3.375
(9) A bus can cover 62.5 km in one hour. How much distance can it cover in 18 hours?
Solution: 62.5 × 18 = 1125 km
(10) A tin of oil weighs 16.8 kg. What is the weight of 45 such tins?
Solution: 45 × 16.8 = 756 kg
(11) A bag of wheat weighs 97.8 kg. How much wheat is contained in 500 such bags?
Solution: 500 × 97.8 = 48900 kg
(12) Find the weight of 16 bags of sugar, each weighing 48.450 kg.
Solution: 48.450 × 16 = 775.2 kg
(13) A small bottle holds 0.845 kg of sauce. How many kg of jam will be there in 72 such bottles?
Solution: 0.845 × 72 = 60.84 kg
(14) A bottle holds 925 g of jam. How many kg of jam will be there in 25 such bottles?
Solution: 925 × 25 = 23125 g = 23.125 kg
(15) If one drum can hold 16.850 litres of oil, how many litres can 48 such drums hold?
Solution: 16.850 × 48 = 808.800 litres
(16) 1 kg of rice costs Rs 56.80. What is the cost of 16.25 kg rice?
Solution: 56.80 × 16.25 = Rs 923
(17) 1 metre of cloth costs Rs 108.50. What is the cost of 18.5 metres of this cloth?
Solution: 108.50 × 18.5 = Rs 2007.25
(18) A car can cover a distance of 8.6 km on one litres of petrol. How far can it go on 36.5 litres of petrol?
Solution: 36.5 × 8.6 = 313.900 km
(19) A taxi driver charges Rs 9.80 per km. How much will he charge for a journey of 106.5 km?
Solution: 106.5 × 9.80 = Rs 1043.70
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