S. K. Gupta Anubhuti Gangal Class 5 Math Eighth Chapter Decimals Exercise 29

S. K. Gupta Anubhuti Gangal Class 5 Math Eighth Chapter Decimals Exercise 29

EXERCISE 29

Add:

(1) 12.67, 4.34

= 12.67 + 4.34

= 17.01

(2) 26.83, 18.45

= 26.83 + 18.45

= 45.28

(3) 5.357, 11.303, 27.152

= 5.357 + 11.303 + 27.152

= 43.812

(4) 425.93, 85.65, 12.96

= 425.93 + 85.65 + 12.96

= 524.54

(5) 83.237, 12.125, 37.489, 52.675

= 83.237 + 12.125 + 37.489 + 52.675

= 185.526

(6) 6.9, 34.05, 9.468         

= 6.9 + 34.05 + 9.468

= 50.418

(7) 175.8, 200.03, 412.358, 18.9

= 175.8 + 200.03 + 412.358 + 18.9

= 807.088

(8) 0.017, 0.1234, 0.9, 0.819, 0.05

= 0.017 + 0.1234 + 0.9 + 0.819 + 0.05

= 1.9094

(9) A tailor needs 52.18 cm of white lace for Rich’s shirt and 75.85 cm of the same lace for the top. How much lace does he need in all?

Solution: The tailor need in all lace (in cm) = 52.18 + 75.85 = 128.03 cm.

(10) Find the perimeter of the adjoining figure?

Solution: Perimeter of the adjoining figure (in cm) = (4.7 + 5.86 + 2.6 + 4.2 + 1.20 +1.20 + 13.43) = 33.19 cm

Find:

(11) 6.253 – 1.678

= 4.575

(12) 312.8 – 59.98

= 252.82

(13) 160 – 39.284

= 120.716

(14) A roll of fabric has 85.63 meters on it. If 43.76 meters are sold, how much is left?

Solution: Left fabric (in meters) = 85.63 – 43.76 = 41.87 meters.

(15) Sharon buys two bottles of perfume; one contains 52.5 mL and the other contains 156.54 mL. How much more perfume is in the larger of the two bottles?

Solution: The larger bottle of perfume (in mL) = 156.54 – 52.5 = 104.04 mL

(16) Sonu runs 153.35 m in 50 seconds and John runs 92.87 m in the same time. How much farther does Sonu run than John?

Simplify: Sonu run than John (in m) = 153.35 – 92.87 = 60.48 m.

(17) 639.209 + 17.813 + 6.275 – 3.468

= 663.297 – 3.468

= 659.829