RS Aggarwal Class 6 Math Fifth Chapter Fractions Exercise 5C Solution
EXERCISE 5C




(9) Reduce each of the following fractions into its simplest form:
(i)
915=9÷315÷3=35
(ii)
4860=48÷1260÷12=45
(iii)
8498=84÷1498÷14=67
(iv)
15060=150÷3060÷30=52
(v)
7290=72÷1890÷18=45
(10) Show that each of the following fractions is in the simplest form:
(i)
811
Here, numerator = 8 and denominator = 11
Factors of 8 are 1, 2, 4, 8
Factors of 11 are 1, 11
Common factor of 8 and 11 is 1 only.
Hence,
811
is in the simplest from.
(ii)
914
Here, numerator = 9 and denominator = 14
Factors of 9 are 1, 3, 9
Factors of 14 are 1, 2, 7, 14
Common factor of 9 and 14 is 1 only.
Hence,
914
is in the simplest from.
(iii)
2536
Here, numerator = 25 and denominator = 36
Factors of 25 are 1, 5, 25
Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36
Common factor of 25 and 36 is 1 only.
Hence,
2536
is in the simplest from.
(iv)
815
Here, numerator = 8 and denominator = 15
Factors of 8 are 1, 2, 4, 8
Factors of 15 are 1, 3, 5, 15
Common factor of 8 and 15 is 1 only.
Hence,
815
is in the simplest from.
(v)
2110
Here, numerator = 21 and denominator = 10
Factors of 21 are 1, 3, 7, 21
Factors of 10 are 1, 2, 5, 10
Common factor of 21 and 10 is 1 only.
Hence,
2110
is in the simplest from.

Leave a Reply